# JE1: Solving Poisson equation on 2D periodic domain¶

## The problem and solution technique¶

With periodic boundary conditions, the Poisson equation in 2D

can be solved using discrete Fourier transforms. Denote the rectangular domain by \(\Omega\) and discretize using \(N_x \times N_y\) cells.

Integrating (1) over \(\Omega\) and using periodicity shows that the source \(s(x,y)\) must satisfy

In the solver implemented in Lucee the source is modified by
subtracting the integrated source from the RHS of (1)
to ensure that this condition is met. Hence, the solution computed by
the updater *does not* satisify (1) but the modified
equation

where \(s_T = \int_\Omega s(x,y) dx dy / |\Omega|\), where
\(|\Omega|\) is the domain volume. Note that for a properly posed
problem the zero integrated source condition *must* be met.

Once the source term is adjusted, its 2D Fourier transform is computed. The Fourier transform of the solution is then

where overbars indicate 2D Fourier transforms and \(k_x\) and \(k_y\) are the wave-numbers. The zero wave-numbers are replaced by \(10^{-8}\) to prevent divide-by-zero. The FFTW library is used to compute the transforms.

The algorithm is implemented in the class `PeriodicPoisson2DUpdater`

class in the `proto`

directory.

This updater is for use in testing finite-volume/finite-difference 2D incompressible flow algorithms. In this entry the stand-alone updater is verified.

## Test Problem 1¶

The domain is assumed to be \(\Omega = [-L_x/2, L_x/2] \times [-L_y/2, L_y/2]\) with \(L_x=L_y=2\) and is discretized using \(128\times 128\) cells. The source is an isotropic Gaussian source of the form

The source and the numerical solution is shown below.

A central difference operator is applied to the computed solution and is compared to the adjusted source. The results are shown below.

## Test Problem 2¶

The domain and resolution are the same as problem 1. The source is an anisotropic Gaussian source of the form

The source and the numerical solution is shown below.

A central difference operator is applied to the computed solution and is compared to the adjusted source. The results are shown below.

## Test Problem 3¶

The domain is assumed to be \(\Omega = [0, L_x] \times [0, L_y]\) with \(L_x=L_y=10\) and is discretized using \(128\times 128\) cells. The source is the sum of two Gaussians given by

where

where \(r_i^2 = (x-x_i)^2 + (y-y_i)^2\) and \((x_1,y_1) = (3.5,5.0)\) and \((x_2,y_2) = (6.5,5.0)\). The source and the numerical solution is shown below.

A central difference operator is applied to the computed solution and is compared to the adjusted source. The results are shown below.

## Test Problem 4¶

This problem is the same as Test Problem 3 except it is discretized using \(128\times 64\) cells. The solutions are shown below.